12-3 Simple way

[tadej5553]

main.m

Code: (Objective-C)

#import <Foundation/Foundation.h> 

#define MAX3(a,b,c) (((a) > (b)) ? (((a) > (c)) ? (a) : (c)) : (((b) > (c)) ? (b) : (c)))

int main (int argc, char *argv[]) 
{ 
    NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init]; 
    
    NSLog(@"Maximum value of 6, 5 and -7 is: %i", MAX3(6, 5, -7));
    
    [pool drain]; 
    return 0; 
}

[rapididy]

a better/shorter way?? Since we already have MAX defined:

#define MAX(a,b) ( ((a) > (b)) ? (a):(b) )
#define MAX3(x,y,z) ( (MAX(x,y)) > (z) ? (MAX(x,y)):(z) )

[skochan]

Or this:

Code: (Objective-C)

#define MAX(x,y,z)  MAX(MAX(x,y), z)

Cheers,

Steve

[piersb]

Oh, that's sneaky. I like.

[Trimakas]

Man.. I aspire to that!!

Todd

[baptzmoffire]

Whoa...you're really blowin' my mind, right now, Steve.   

[eagle74]

Whoa...you're really blowin' my mind, right now, Steve.   

It's true!!