Amazon.com Widgets Does this look good - Exercise 7.2 (+Question)
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+ Official Forum for Programming in Objective-C (the iPhone Programming Language) - Stephen Kochan
|-+ Programming in Objective-C, 4th edition
| |-+ Exercises
| | |-+ Chapter 7
| | | |-+ Does this look good - Exercise 7.2 (+Question)
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Author Topic: Does this look good - Exercise 7.2 (+Question) (Read 948 times)
MCaEd
Newbie
*
Posts: 49






on: February 21, 2012, 05:52:27 PM

I ended up with this code:
Code: (Objective-C)
-(void) print: (BOOL) redu
{
    Fraction *tempo = [[Fraction alloc] init];
    [tempo setTo: numerator over: denominator];
   
    int u = numerator;
    int v = denominator;
    int temp;
   
    while (v != 0)
    {
        temp = u % v;
        u = v;
        v = temp;
    }
   
    if (u != 1)
        redu = YES;
    else
        redu = NO;
   
    if (redu)
    {
        tempo.numerator /= u;
        tempo.denominator /= u;
    }
    else if (!tempo.numerator)
        NSLog (@"0 (zero)");
    else if (tempo.denominator == 1)
        NSLog (@"%i", tempo.numerator);
    else
        NSLog (@"%i/%i", numerator, denominator);
}
What do you think? I included part of the reduce method here since I think we should check first whether the fraction needs to be reduced rather than take the fraction through the reduce method anyways.

Also, I haven't actually realized that we can use other methods inside a method. Is it true since I don't remember any mentions in the book.

Thank you.
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jgross
Newbie
*
Posts: 8






Reply #1 on: February 29, 2012, 11:28:12 PM

Yes, methods can be called from within other methods.  To call a method from the same object, use the self declaration:
Code: (Objective-C)
-(void) add: (Fraction *) f{
    numerator = numerator * f.denominator + f.numerator * denominator;
    denominator *= f.denominator;
    [self reduce];
}
You can also call methods to apply to other objects, like so:
Code: (Objective-C)
-(Fraction *) add: (Fraction *) f{
    Fraction *result = [Fraction new];
    result.numerator = numerator * f.denominator + f.numerator * denominator;
    result.denominator = denominator * f.denominator;
    [result reduce];
    return result;
}

More experienced members may have more detailed answers or better examples.

Jim
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