There is no operator to do this in Objective-C.  The Standard C Library has an exp (x, y) that raises x to the y power, but it works all in doubles.

Cheers,

Steve Kochan

Yeah, that's it.  Thanks for pointing that out!

Cheers,


Steve Kochan

The compiler will cast the ints into doubles for you. But it wouldn't be a bad practice to explicitly cast them yourself.

resultInt = (int)pow((double)someInt, (double)someOtherInt);

Be aware however, that if the result of the pow function is greater than the maximum value an int can hold, the value of the int won't be what you expected.

#import <Foundation/Foundation.h>

int main (int argc, const char * argv[])
{
  NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];

  NSLog(@"(double)pow(2, 32)                    = %lf", (double)pow(2, 32));
  NSLog(@"(short int)pow(2, 32)                 = %hi", (short int)pow(2, 32));
  NSLog(@"(unsigned short int)pow(2, 32)        = %hu", (unsigned short int)pow(2, 32));
  NSLog(@"(int)pow(2, 32)                       = %i" , (int)pow(2, 32));
  NSLog(@"(unsigned int)pow(2, 32)              = %u" , (unsigned int)pow(2, 32));
  NSLog(@"(long long int)pow(2, 32)             = %qi", (long long int)pow(2, 32));
  NSLog(@"(unsigned long long int)pow(2, 32)    = %qu", (unsigned long long int)pow(2, 32));

  [pool drain];
  return 0;
}