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Author Topic: Page 446 won't work. (Read 1526 times)
Posts: 3

on: March 16, 2010, 06:42:41 AM

NSLog(@"%@\n%i\n%g", [myFoo2 strVal], [myFoo2 intVal], [myFoo2 floatVal]);

I've confirmed that strVal will NOT print. intVal and floatVal print just fine. I get the error message "Program received signal: "EXC_BAD_ACCESS""
Hero Member
Posts: 3114

Reply #1 on: March 16, 2010, 07:42:47 AM

That example does work.  Can you re-check your code or post it here?


Steve Kochan
Posts: 3

Reply #2 on: March 17, 2010, 06:28:32 PM

Found the problem while replying: I forgot to retain strVal after decoding.

#import <Foundation/Foundation.h>

@interface Foo : NSObject <NSCoding>
   NSString *strVal;
   int intVal;
   float floatVal;

@property (copy, nonatomic) NSString *strVal;
@property int intVal;
@property float floatVal;


@implementation Foo

@synthesize strVal, intVal, floatVal;

- (NSString *) stringValue {
   return strVal;

- (void) encodeWithCoder:(NSCoder *) coder {
   [coder encodeObject: strVal forKey: @"FoostrVal"];
   [coder encodeInt: intVal forKey: @"FoointVal"];
   [coder encodeFloat: floatVal forKey: @"FoofloatVal"];

- (id) initWithCoder:(NSCoder *) decoder {
   strVal = [decoder decodeObjectForKey: @"FoostrVal"];
   intVal = [decoder decodeIntForKey: @"FoointVal"];
   floatVal = [decoder decodeFloatForKey: @"FoofloatVal"];
   return self;


int main (int argc, const char * argv[]) {
    NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];
   Foo *myFoo1 = [[Foo alloc] init];
   Foo *myFoo2;
   [myFoo1 setStrVal: @"This is the string"];
   [myFoo1 setIntVal: 12345];
   [myFoo1 setFloatVal: 98.6];
   [NSKeyedArchiver archiveRootObject: myFoo1 toFile: @"foo.arch"];
   myFoo2 = [NSKeyedUnarchiver unarchiveObjectWithFile: @"foo.arch"];
   NSLog(@"%@\n%i\n%g", [myFoo2 strVal],[myFoo2 intVal], [myFoo2 floatVal]);
   [myFoo1 release];
    [pool drain];
    return 0;

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